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十字相乘法分解因式练习题及答案

2021-12-16 来源:华佗健康网


十字相乘法分解因式

x25x6 x25x6 x25x6 x25x6

x23x2 x23x2 x22x3 x22x3

~

x2x2

x212x32

2x25x2

2x27x3 (

3x27x6

x24x12 x210x9 2x25x3 2x27x3 3x28x3 x22x63 x23x10 2x23x20 2x27x6 3x25x2 x28x15

x22x15

2x25x7 2x2+7x+6

5x23x2

5x26x8 6x25x25 6x27x3 4x2+15x+9

x27x6 x213x36 x25x24 x22x15

~

x22x3 4m28mn3n2 5x26xy8y2 6y211y10

-

8x226xy15y2 (x2x)28(x2x)12 3a2b217abxy10x2y2 x34x221x

5a2b223ab10 = x211xy18y2 x2y25x2y6x2 3x310x23x=

(2x3)23(2x3)2 (x28x)222(x28x)120

~

用因式分解法列下列方程:

/

a2-7a+6=0 8x2+6x-35=0 18x

2x2+3x+1=0 2y2+y-6=0 6x

6x2-11x+3=0 4m2+8m+3=0 10x ·

4n2+4n-15=0 6a2+a-35=0 5x

15x2+x-2=0 6y2+19y+10=0

'

3x2 +7x-6=0 x2 + 2x-3 = 0 2x

2-21x+5=0 202-13x+6=0 3a2-21x+2=0 8m2-8x-13=0 4x2x23x20=0 2x2-7x + 6 = 0 x(x-9y-20y2=0 2-7a-6=0 2-22m+15=0 2+15x+9=0 2 +5x+2=0 -2) = 3

2x-5xy+2y=0 (2x-3)2 + 3(2x-3) + 2 = 0

22

^

答案 x25x6 x25x6 、x25x6 x25x6 =(x-1)(x+6) x23x2 =(x+6)(x-1) x22x3 =(x-6)(x+1) x22x3 =(x-2)(x-3) x23x2 (=(x+1)(x+2) x2x2 x24x12 =(x+3)(x-1) x22x63 =(x-3)(x+1) x28x15 =(x-1)(x-2) =(x+2)(x-1) x212x32 > x210x9 =(x+9)(x-7) x23x10 =(x-3)(x-5) x22x15 =(x-6)(x+2) =(x+4)(x+8) 2x25x2 ^ =(x-5)(x+2) 2x23x20 =(x-5)(x+3) 2x25x7 =(x+1)(x+9) 2x25x3 [=(2x+1)(x+2) 2x27x3 =(2x+5)(x-4) 2x27x6 =(2x+7)(x-1) 2x+7x+6 =(2x+3)(2x+2) 5x23x2 2=(2x+1)(x-3) 2x27x3 $=(2x+1)(x+3) 3x27x6 =(2x-3)(x-2) 3x25x2 =(2x-1)(x-3) ` 3x28x3 =(3x-2)(x+3) =(3x-2)(x-1) =(5x+2)(x-1) =(3x-1)(x+3)

5x6x8 2# 6x7x3 2=(5x-4)(x+2) x27x6 $6x25x25 =(2x-3)(3x+1) x25x24 24x+15x+9 =(x+3)(4x+3) =(3x+5)(2x-5) x213x36 x22x15 =(x+4)(x+9) 4m28mn3n2 =(x+8)(x-3) 5x26xy8y2 =(x-5)(x+3) 6y211y10 =(x-1)(x-6) x22x3 ' =(2m+n)(2m+3n) (x2x)28(x2x)12=(5x+4y)(x-2y) =(2y-5)(3y+2) =(-x+3)(x+1) 8x226xy15y2 (3a2b217abxy10x2y2x34x221x (x+3) =(ab-5xy)(3ab-=x(x-7)2xy) =(2x-1)(4x+15) 5a2b223ab10 =(x+x-2)(x+x-6) x211xy18y2 、22x2y25x2y6x2 (x y-6x)(x y+x) 3x310x23x =3(3x-1)(x-3) =(ab+5)(5ab-2) (x+9y)(x+2y) (2x3)23(2x3)2 =(2x-2)(2x-1)=2(x-1)(2x-1) (x28x)222(x28x)120 * =(x2+8x+10)(x+2)(x+6) a2-7a+6=0 =(a-1)(a-6) 2x2+3x+1=0 (2x+1)(x+1) 6x2-11x+3=0 (3x-1)(2x-3) 4n+4n-15=0 (2n-3)(2n+5) 15x2+x-2=0 (3x-1)(5x+2) 3x2 +7x-6=0 (x+3)(3x-2) 2x-5xy+2y=0 2228x2+6x-35=0 (2x+5)(4x-7) 2y2+y-6=0 (2x-3)(x-2) 4m2+8m+3=0 (2m+1)(2m+3) 6a+a-35=0 (2a+5)(3a-7) 6y2+19y+10=0 (2y+5)(3y+2) x2 + 2x-3 = 0 (x-1)(x+3) 218x2-21x+5=0 (3x-1)(6x-5) 6x2-13x+6=0 (2x-3)(3x-2) 10x2-21x+2=0 (10x-1)(x-2) 5x-8x-13=0 (x-1)(5x+13) 2x23x20=0 220-9y-20y2=0 · (4-5y)(5+4y) 3a2-7a-6=0 ~ (3a+2)(a-3) 8m2-22m+15=0 [ (2m-3)(4m-5) 4x2+15x+9=0 ^ (4x+3)(x+3) 2x2 +5x+2=0 (x+2)(2x+1) x(x-2) = 3 (x-4)(2x+5) 2x2-7x + 6 = 0 (x-3)(2x-1) (x-3)(x+1) (2x-3)2 + 3(2x-3) + 2 = 0 =(2x-2)(2x-1)=2(x-1)(2x-1)

(x-2y)(2x-y)

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